x^2/10-3x=0

Solution for x^2/10-3x=0 equation:

x^2/10-3x=0

We multiply all the terms by the denominator


x^2-3x*10=0

Wy multiply elements

x^2-30x=0

a = 1; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·1·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*1}=\frac{60}{2}
=30
$